Due to increase of k% in the side, the area of a square increases by 69%. What is the value of k?
Let side of square = $$10$$ cm
=> Area of square = $$(10)^2=100$$ $$cm^2$$
Area is increased b 69%, => New area = $$100+(\frac{69}{100}\times100)=169$$ $$cm^2$$
Thus, new side of square = $$\sqrt{169}=13$$ cm
$$\therefore$$ Increase in side = $$k=\frac{(13-10)}{10}\times100$$
= $$30\%$$
=> Ans - (A)
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