A starts from a point at a speed of 30 metre/second. After 3 seconds, B starts chasing A from the same point with a speed of 50 metre/second. What will be the total distance (in metres) travelled by A and B before A is caught by B?

Speed of A = 30 m/s and speed of B = 50 m/s

Distance covered by A in 3 seconds = $$3\times30=90$$ m

Since, they are moving in same direction, thus relative speed = $$50-30=20$$ m/s

Time taken by B to overtake A = $$\frac{90}{20}=4.5$$ s

Thus, A travelled for 7.5 seconds and B for 4.5 seconds.

$$\therefore$$ Total distance (in metres) travelled by A and B before A is caught by B = $$(30\times7.5)+(50\times4.5)$$

= $$225+225=450$$ m

=> Ans - (B)