A group of 200 people are chosen randomly at a conference. Later, it was found that 120 of them like blue pens and 140 like green pens while 70 like both green and blue pens. Determine the number of people thus chosen who do not like neither green nor blue pens ?
Solution
Let:
Total people = 200
Like Blue = 120
Like Green = 140
Like both = 70
We can use the Inclusion-Exclusion Principle.
Like at least one=120 + 140 − 70 = 190
Hence, liked neither: 200 − 190 = 10
Therefore, the answer is 10 people.
Get AI Help
Create a FREE account and get:
- Download Maths Shortcuts PDF
- Get 300+ previous papers with solutions PDF
- 500+ Online Tests for Free
Book Free CAT Mentorship
Get personalized CAT strategy from a 99%iler
500+ students mentored
OTP Verification
Enter the 6-digit code sent to your phone
Booking Summary
Enter OTP
Didn't receive the OTP?
