What is the value of $$\left\{\frac{(0.7)^2 \div 0.14 + (0.6)^2 \div 0.18 + (0.5)^2 \div 0.05}{4(2.5  of  4 - 13 \times 0.25 \times 3)}\right\}$$?

Firstly solve bracket then apply bodmass

 $$\left\{\frac{(0.7)^2 \div 0.14 + (0.6)^2 \div 0.18 + (0.5)^2 \div 0.05}{4(2.5  of  4 - 13 \times 0.25 \times 3)}\right\}$$

 $$\left\{\frac{0.49 \div 0.14 + 0.36 \div 0.18 + 0.25 \div 0.05}{4(10 - 13 \times 0.25 \times 3)}\right\}$$

 $$\left\{\frac{\frac {7}{2} + 2 + 5}{4(10 - 13 \times 0.25 \times 3)}\right\}$$

$$\left\{\frac{\frac {21}{2}}{4(10 - 9.75)}\right\}$$

$$\left\{\frac{\frac {21}{2}}{4(10 - 9.75)}\right\}$$

$$\frac{21}{2}$$