If $$\sec \theta$$ and $$\sin \theta (0 < \theta < 90)$$ are the roots of the equation $$\sqrt 6x^2 - kx + \sqrt 6 = 0.$$ then the value of k is:

A

$$3 \sqrt 3$$

B

$$2 \sqrt 3$$

C

$$\sqrt 3$$

D

$$3 \sqrt 2$$