Instructions
In a certain code, $$n^{th}$$ letter in t he English alphabet is coded as $$(n + 4) (mod 26)^{th}$$ letter if n is even and (n - 4) $$(mod 26)^{th}$$ letter if n is odd. The inverse process is used for decoding.
Using this information answer the questions from 56 to 60.
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