Question 56

30 men working 5 hours a day can do a task in 16 days. In how many days will 40 men working 6 hours a day do the same task?

Solution

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Let the required number of days be x.

A/c to question ,

$$M_{1}T_{1}D_{1} = M_{2}T_{2}D_{2}$$

$$30 \times 5 \times 16 = 40 \times 6 \times x$$

x = 10

So, the answer would be option b)10 days

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