30 men working 5 hours a day can do a task in 16 days. In how many days will 40 men working 6 hours a day do the same task?
Let the required number of days be x.
A/c to question ,
$$M_{1}T_{1}D_{1} =Â M_{2}T_{2}D_{2}$$
$$30 \times 5 \times 16 = 40 \times 6 \times x$$
x = 10
So, the answer would be option b)10 days
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