Instructions
Find the wrong number in given series sequence.
Solution
4 = 1*2+2 ; 15 = 4*3+3 ; 64 = 15*4+4 ; 325 = 64*5+5 ; 1956 = 325*6+6
The nth term is of the form,
$$T_n=(T_{n-1}\times n)+n$$
The last term does not follow the pattern and is thus the wrong number in the sequence.
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