Solution
$$8\div[(9-5)\div(7-2)\div(3+9\div24)]$$
$$=8\div[(9-5)\div(7-2)\div(3+\frac{3}{8})]$$
$$=8\div[(9-5)\div(7-2)\div\frac{27}{8}]$$
$$=8\div[(9-5)\div5\div\frac{27}{8}]$$
$$=8\div[4\div\frac{40}{27}]$$
$$=8\div\frac{27}{10}$$
$$=\frac{80}{27}.$$
A is correct choice.
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