Question 55

Ina circle with center O and radius 10 cm, PQ and RS are two parallel chords of lengths x cm and 12 cm, respectively, and both the chords are on the opposite side of O. If the distance between PQ and RS is 14 cm,the value of x is:

Solution

Now OM =a ; ON =14-a
Now a^2+6^2 =10^2
we get a =8
so ON =6
Now RN = 8
So RS =16

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