Solution
$$2x + \frac{1}{3x} = 6$$
Multiply both sides with $$\frac{3}{2}$$ to get:
$$\frac{3}{2}\left(2x+\frac{1}{3x}\right)\ =\ \frac{3}{2}\times\ 6$$
$$3x+\frac{1}{2x}=9$$.
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