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Question 55
A hollow copper pipe is 22 cm long and its external diameter is 28 cm.If the thickness of the pipe is 3 cm and iron weighs 8.5 g/cm$$^3$$, then the weight of the pipe is closest to:
Solution
External radius = 14 cm
Thickness of the pipe = 3 cm
Then, Internal radius = 14-3 = 11 cm
Volume of the pipe = $$\dfrac{22}{7} \times (14^2 - 11^2) \times 22 = \dfrac{22}{7} \times 75 \times 22 = 5185.71 cm^3$$
Weight of the pipe per $$cm^3 = 8.5 gm$$
Total weight of the pipe = $$5185.71 \times 8.5 = 44078.5 gm = 44 kg$$
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