X borrowed some money from a source at 8% simple interest and lent it to Y at 12% simple interest on the same day and gained Rs. 4,800 after 3 years. The amount X borrowed, (in Rs.), is

Let amount that X borrowed = Rs. $$100x$$

Simple interest = $$\frac{P\times R\times T}{100}$$

Interest X need to return to the source at 8% in 3 years

= $$A=\frac{100x\times8\times3}{100}=Rs.$$ $$24x$$

Similarly, interest X get from Y = $$A'=\frac{100x\times12\times3}{100}=Rs.$$ $$36x$$

According to ques,

=> $$A'-A=4800$$

=> $$36x-24x=12x=4800$$

=> $$x=\frac{4800}{12}=400$$

$$\therefore$$ Amount X borrowed = $$100\times400=Rs.$$ $$40,000$$

=> Ans - (D)