Raju has to cover a distance of 240 km in 4 hours. If he covers one-third of the journey in 2/7th time, what is his speed at the beginning of the journey?
Distance covered = $$\frac{1}{3}\times240=80$$ km
Time taken =Â $$\frac{2}{7}\times4=\frac{8}{7}$$ hr
=> Speed = distance/time
= $$80\div\frac{8}{7}$$
= $$80\times\frac{7}{8}$$
= $$10\times7=70$$ km/hr
=> Ans - (A)
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