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Instructions
Answer the questions based on the following information. A cow is tethered at point A by a rope. Neither the rope nor the cow is allowed to enter ΔABC.
∠BAC = 30°
I(AB) = I(AC) = 10 m
Solution
Area grazed by cow will be = (circle passing through P and Q) - (Area of circle inside the triangle)
= $$\pi r^2 - \frac{\pi r^2}{12}$$ = $$\frac{176\pi}{3}$$
Area grazed by cow will be = (circle passing through P and Q) - (Area of circle inside the triangle)
= $$\pi r^2 - \frac{\pi r^2}{12}$$ = $$\frac{176\pi}{3}$$
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