Question 54

The volume of the water in two tanks, A and B,is in the ratio of 6 : 5. The volume of water in tank A is increased by 30%. By what percentage should the volume of water in tank B be increased so that both the tanks have the same volume of water?

Solution

Let the volume of water in tanks A and B are $$6p$$ and $$5p$$ respectively

Volume of water in tank A after increasing 30% = $$\frac{130}{100}\times6p=7.8p$$

Volume of water to be increased in tank B to have same volume as tank A = $$7.8p-5p=2.8p$$

$$\therefore\ $$Percentage increase in volume of water in tank B = $$\frac{2.8p}{5p}\times100=56\%$$

Hence, the correct answer is Option A

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