The volume of a solid sphere is 4851 $$m^3$$. What is the surface area of the sphere?(Take $$\pi = \frac{22}{7}$$)
Volume of the sphere = $$4851m^3$$
Let the radius of the sphere = r m
$$\dfrac{4}{3} \times \dfrac{22}{7} \times r^3 = 4851$$
=> $$r^3 = \dfrac{21^3}{2^3} => r = \dfrac{21}{2}$$
Surface area $$= 4 \times \dfrac{22}{7} \times \dfrac{21}{2} \times \dfrac{21}{2} = 1386 m^2$$
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