Question 54
The table givens below presents rainfall (in mm) in two cities on different days of a week.
The rainfall on day D2 in City 1 is how much percent more than the rainfall on day D4 in City 2?
Solution
The rainfall on day D2 in City 1 = 78
The rainfall on day D4 in City 2 = 77.7
Required percentage = $$\frac{78 - 77.7}{77.7} \times 100$$ = $$\frac{100}{259}$$
So , the answer would be option a)$$\frac{100}{259}$$
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