Question 54

The table givens below presents rainfall (in mm) in two cities on different days of a week.


The rainfall on day D2 in City 1 is how much percent more than the rainfall on day D4 in City 2?

Solution

The rainfall on day D2 in City 1 = 78

The rainfall on day D4 in City 2 = 77.7

Required percentage = $$\frac{78 - 77.7}{77.7} \times 100$$ = $$\frac{100}{259}$$

So , the answer would be option a)$$\frac{100}{259}$$


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