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The hydraulic diameter, $$D_h$$, of a rectangular channel with sides ‘a’ and ‘b’ is
$$D_h = \frac{4ab}{2a + b}$$
$$D_h = \frac{2ab}{a + b}$$
$$D_h = \frac{2ab}{2a + b}$$
$$D_h = \frac{4ab}{a + b}$$
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