The average of 33 numbers is 74. The average of the first 17 numbers is 72.8 and that of the last 17 numbers is 77.2. If the $$17^{th}$$ number is excluded, then what will be the average of the remaining numbers (correct to one decimal place)?

Average = sum of the terms/number of terms
Sum of the 33 numbers = 74 $$\times$$ 33 = 2442
The average of the first 17 numbers = 72.8
Sum of the first 17 numbers = 72.8 $$\times$$ 17 = 1237.6
The average of the last 17 numbers = 77.2
Sum of the first 17 numbers = 77.2 $$\times$$ 17 = 1312.4
$$17^{th}$$ number = sum of the first 17 numbers + sum of the last 17 numbers - sum of the 33 numbers= 1237.6 + 1312.4 -2442 = 108
Sum of the 32 numbers without $$17^{th}$$ number = 2442 - 108 = 2334
Average of 32 numbers = 2334/32 = 72.93