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Question 53
If $$(5x + 1)^3 + (x - 3)^3 + 8(3x - 4)^3 = 6(5x + 1)(x -Â 3)(3x -Â 4)$$,$$ then $$x$$ is equal to:
Solution
$$(5x + 1)^3 + (x - 3)^3 + 8(3x - 4)^3Â = 6(5x + 1)(x - 3)(3x - 4)$$
$$(5x + 1)^3 + (x - 3)^3 + (6x - 8)^3= 3(5x + 1)(x - 3)(6x - 8)$$
When $$a^3 + b^3 + c^3$$ = 3abc then a + b + c = 0.
5x + 1 +Â x - 3 +Â 6x - 8 = 0
12x = 10
x = 5/6
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