Please enter the following details
Free Daily Targets & Mocks
Study Material & Formulas PDFs
1 on 1 Mentorship
Question 53
The value of $$\sin^2 64^\circ + \cos 64^\circ \sin 26^\circ + 2 \cos 43^\circ \cosec 47^\circ$$ is:
Solution
$$\sin^2 64^\circ + \cos 64^\circ \sin 26^\circ + 2 \cos 43^\circ \cosec 47^\circ$$
=Â $$\sin^2 64^\circ + \cos 64^\circ \sin(90 -Â 64^\circ) + 2 \cos 43^\circ \cosec(90 - 43^\circ)$$
= $$\sin^2 64^\circ + \cos^2 64^\circ + 2 \cos 43^\circ se43^\circ$$
= $$1 + 2$$ = 3
Create a FREE account and get:
- Free SSC Study Material - 18000 Questions
- 230+ SSC previous papers with solutions PDF
- 100+ SSC Online Tests for Free
