The value of $$\sin^2 64^\circ + \cos 64^\circ \sin 26^\circ + 2 \cos 43^\circ \cosec 47^\circ$$ is:
$$\sin^2 64^\circ + \cos 64^\circ \sin 26^\circ + 2 \cos 43^\circ \cosec 47^\circ$$
=Â $$\sin^2 64^\circ + \cos 64^\circ \sin(90 -Â 64^\circ) + 2 \cos 43^\circ \cosec(90 - 43^\circ)$$
= $$\sin^2 64^\circ + \cos^2 64^\circ + 2 \cos 43^\circ se43^\circ$$
= $$1 + 2$$ = 3
Create a FREE account and get:
By proceeding you agree to create your account
Otp is sent to the requested phone number
Wrong OTP Entered
Email already Exists !!! Retry with another email
Something went wrong !!!
