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Question 53
In the following equation, if the mathematical operators '-' and '$$\times$$' are interchanged then the value of 4 — 6 + 1 $$\times$$ 15 $$\div$$ 3 will be
Solution
4 — 6 + 1 $$\times$$ 15 $$\div$$ 3
$$4\times 6 + 1 -15\div 3$$
Applybodmass rule
$$4\times 6 + 1 -15\div 3$$
$$4\times 6 + 1 -5$$
$$24 + 1 -5$$
20
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