If $$3^{\sqrt[3]{x}} + 4^{\sqrt[3]{x}} = 5^{\sqrt[3]{x}}$$ then the value of $$x$$ is:
We know thatÂ
3,4,5 forms a pythagorean triplet as $$3^2+4^2\ =\ 5^2$$
By Comparing , we getÂ
 $$\sqrt[\ 3]{x}=2$$
$$x=2^3$$
so, x =8
Hence , option d is correct.
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