Question 53

$$\frac{(0.87)^3 + (0.13)^3}{(0.87)^2 + (0.13)^2 - (0.87) \times (0.13)}$$ is equal to

using identity $$ a^3 + b^3 = (a + b)(a^2 - ab + b^2) $$

here a = 0.87

b = 0.13

$$\frac{(0.87)^3 + (0.13)^3}{(0.87)^2 + (0.13)^2 - (0.87) \times (0.13)} = \frac{(0.87 + 0.13)(0.87)^2 + (0.13)^2 - (0.87) \times (0.13)}{(0.87)^2 + (0.13)^2 - (0.87) \times (0.13)} = 0.87 + 0.13 =1 $$

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