Question 53

Find the HCF of 48, 92 and 140.

Solution

We will find the prime factorisation

48 = $$1\times\ 2^4\times\ 3 $$

92 = $$1\times\ 2^2\times\ 23$$

140 = $$1\times\ 2^2\times\ 5\times\ 7$$

Highest common factor is $$2^2$$ = 4.

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