Find the HCF of 48, 92 and 140.
We will find the prime factorisation
48 =Â $$1\times\ 2^4\times\ 3 $$
92 =Â $$1\times\ 2^2\times\ 23$$
140 =Â $$1\times\ 2^2\times\ 5\times\ 7$$
Highest common factor is $$2^2$$ = 4.
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