Question 53

A ship after sailing 12 km towards south from a particular place covered 5 km more towards east. Then the straightway distance of the ship from that place is

Solution

Let the ship started from point A and sailed 12 km south to reach B, and then turned east and finally reached C after travelling 5 km.

Thus, $$(AC)^2=(AB)^2+(BC)^2$$

=> $$(AC)^2=(12)^2+(5)^2$$

=> $$(AC)^2=144+25=169$$

=> $$AC=\sqrt{169}=13$$ km

=> Ans - (D)

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