Question 52
A tangent is drawn to a circle of radius 6 cm from a point situated at a distance of 10 cm from the centre of the circle. The length of the tangent will be
Solution
radius OA = 6 and OB = 10
Now, in $$\triangle$$OAB right angle at A
AB = $$\sqrt{(OB)^2 - (OA)^2}$$
= $$\sqrt{100-36} = \sqrt{64}$$
= 8 cm
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