Question 52

A tangent is drawn to a circle of radius 6 cm from a point situated at a distance of 10 cm from the centre of the circle. The length of the tangent will be

Solution

radius OA = 6 and OB = 10

Now, in $$\triangle$$OAB right angle at A

AB = $$\sqrt{(OB)^2 - (OA)^2}$$

= $$\sqrt{100-36} = \sqrt{64}$$

= 8 cm


Create a FREE account and get:

  • Free SSC Study Material - 18000 Questions
  • 230+ SSC previous papers with solutions PDF
  • 100+ SSC Online Tests for Free

cracku

Boost your Prep!

Download App