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The resultant of two forces P and Q acting at an angle $$\theta$$, is given by :
$$\sqrt{P^2 + Q^2 + 2PQtan\theta}$$
$$\sqrt{P^2 + Q^2 + 2PQsin\theta}$$
$$\sqrt{P^2 + Q^2 + 2PQcos\theta}$$
$$P^2 + Q^2 + 2PQtan\theta$$
So, the answer would be option c)$$\sqrt{P^2 + Q^2 + 2PQcos\theta}$$
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