Let's assume the required time is 'n'.
$$Amount = principal\left(1+\frac{rate}{100}\right)^{time}$$
$$12167 = 8000\left(1+\frac{15}{100}\right)^{n}$$
$$12167 = 8000\left(1+\frac{3}{20}\right)^{n}$$
$$\frac{12167}{8000} = \left(\frac{23}{20}\right)^{n}$$
$$(\frac{23}{20})^{3} = \left(\frac{23}{20}\right)^{n}$$
So n = 3 years [by comparing the power of both of the sides]
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