Question 52

Find the value of $$\frac{(82 + 28)^2 - (82 - 28)^2}{82 \times 28}$$.

Solution

$$\frac{(82 + 28)^2 - (82 - 28)^2}{82 \times 28}$$.

$$(a + b)^2 = a^2 + b^2 + 2ab$$

$$(a - b)^2 = a^2 + b^2 - 2ab$$

apply this rule In equation

$$\frac{82^2 + 28^2 + 2\times 82\times 28 -(82^2 + 28^2 - 2\times 82\times 28)}{82 \times 28}$$.

= 4

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