Solution
$$\frac{(82 + 28)^2 - (82 - 28)^2}{82 \times 28}$$.
$$\frac{(82 + 28)^2 - (82 - 28)^2}{82 \times 28}$$.
$$(a + b)^2 = a^2 + b^2 + 2ab$$
$$(a - b)^2 = a^2 + b^2 - 2ab$$
apply this rule In equation
$$\frac{82^2 + 28^2 + 2\times 82\times 28 -(82^2 + 28^2 - 2\times 82\times 28)}{82 \times 28}$$.
= 4
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