A can do a piece of work in 18 days. He worked at it for 12 days and B finished the remaining work in 8 days. B alone can do the whole work in
Let total work to be done = 36 units
A can do the work in 18 days.
=> A's efficiency = $$\frac{36}{18}=2$$ units/day
Work done by A in 12 days = $$2 \times 12=24$$ units
Thus, work left = $$36-24=12$$ units
This work is done by B in 8 days.
=> B's efficiency = $$\frac{12}{8}=1.5$$ units/day
$$\therefore$$ Time taken by B alone to finish the work = $$\frac{36}{1.5}=24$$ days
=> Ans - (B)
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