Question 52

A can do a piece of work in 18 days. He worked at it for 12 days and B finished the remaining work in 8 days. B alone can do the whole work in

Solution

Let total work to be done = 36 units

A can do the work in 18 days.

=> A's efficiency = $$\frac{36}{18}=2$$ units/day

Work done by A in 12 days = $$2 \times 12=24$$ units

Thus, work left = $$36-24=12$$ units

This work is done by B in 8 days.

=> B's efficiency = $$\frac{12}{8}=1.5$$ units/day

$$\therefore$$ Time taken by B alone to finish the work = $$\frac{36}{1.5}=24$$ days

=> Ans - (B)

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