Statements: E \geq P \geq X > R = S \geq T Conclusion I: T < P Conclusion II: X < E

Question 51

Statements: E $$\geq$$ P $$\geq$$ X > R = S $$\geq$$ T
Conclusion I: T < P
Conclusion II: X < E

Solution

T < = S < X <=P. Thus, T < X <=P. Hence, T < P. Thus conclusion I follows. X < = P < = E. As X=P=E is a possibility, we cannot say X<E. Hence, only conclusion I follows.

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Statements: E $$\geq$$ P $$\geq$$ X > R = S $$\geq$$ T Conclusion I: T < P Conclusion II: X < E

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Statements: E $$\geq$$ P $$\geq$$ X > R = S $$\geq$$ T
Conclusion I: T < P
Conclusion II: X < E