In $$\triangle PQR,$$ S and T are mid-points of PQ and PR, respectively. If $$\angle QPR = 75^\circ$$ and $$\angle PRQ = 40^\circ$$, then $$\angle TSQ$$ is:

A

$$105^\circ$$

B

$$135^\circ$$

C

$$115^\circ$$

D

$$120^\circ$$