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Question 51
If the distance between the plane $$Ax - 2y + z = d$$ and the plane containing the lines $$\frac{x-1}{2} = \frac{y-2}{3} = \frac{z-3}{4}$$ and $$\frac{x-2}{3} = \frac{y-3}{4} = \frac{z-4}{5}$$ is $$\sqrt{6}$$, then $$\mid d \mid$$ is
Correct Answer: 6
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