Sign in
Please select an account to continue using cracku.in
↓ →
The ratio of the present age of a man and his wife is 4:3 and 4 years hence the ratio of their ages will be 9:7 If the ratio of their ages at the time of their marriage was 13:9, how many years ago were they married ?
Let the ages today be 4x and 3x. Ages four years from now are 4x + 4 and 3x + 4Β
But 4x+4:3x+4 = 9:7
So, x = 8
So, their current ages = 32 and 24
Let them be married for x years
Age at marriage = 32 - x and 24 - x
But 32 - x : 24 - x = 13: 9Β
So Β x = 6 years.Β
Was this solution helpful?
Create a FREE account and get:
Book Free CAT Mentorship
Get personalized CAT strategy from a 99%iler
500+ students mentored
OTP Verification
Enter the 6-digit code sent to your phone
Booking Summary
Enter OTP
Didn't receive the OTP?
Start your IIM journey with the right preparation and crack CAT 2026.
Educational materials for CAT preparation