Match the catalysts to the correct process.

Catalyst     Process
A. $$TiCl_3$$     i. Wacker process
B. $$PdCl_2$$     ii. Ziegler-Natta polymerisation
C. $$CuCl_2$$     iii. Contact process
D. $$V_2O_5$$     iv. Deacon's process

Let's solve this matching question step by step. We need to match each catalyst to the correct process. The catalysts are A. TiCl₃, B. PdCl₂, C. CuCl₂, D. V₂O₅, and the processes are i. Wacker process, ii. Ziegler-Natta polymerisation, iii. Contact process, iv. Deacon's process.

First, recall that the Ziegler-Natta polymerisation is used for polymerising alkenes like ethylene or propylene into polymers. The catalyst for this process is typically a combination of titanium compounds (such as TiCl₃ or TiCl₄) and aluminium alkyls. Therefore, catalyst A (TiCl₃) is used in process ii (Ziegler-Natta polymerisation). So, A matches with ii.

Next, the Wacker process converts ethylene (C₂H₄) to acetaldehyde (CH₃CHO) using oxygen. The catalyst for this process is palladium chloride (PdCl₂). Thus, catalyst B (PdCl₂) is used in process i (Wacker process). So, B matches with i.

Now, Deacon's process is used to produce chlorine (Cl₂) from hydrogen chloride (HCl) and oxygen. The catalyst for this reaction is copper(II) chloride (CuCl₂). Hence, catalyst C (CuCl₂) is associated with process iv (Deacon's process). So, C matches with iv.

Finally, the Contact process is used to manufacture sulfuric acid (H₂SO₄) from sulfur dioxide (SO₂) and oxygen. The catalyst employed here is vanadium pentoxide (V₂O₅). Therefore, catalyst D (V₂O₅) corresponds to process iii (Contact process). So, D matches with iii.

Summarizing the matches:

• A (TiCl₃) → ii (Ziegler-Natta polymerisation)
• B (PdCl₂) → i (Wacker process)
• C (CuCl₂) → iv (Deacon's process)
• D (V₂O₅) → iii (Contact process)

Now, comparing with the given options:

• Option A: A → iii, B → i, C → ii, D → iv
• Option B: A → iii, B → ii, C → iv, D → i
• Option C: A → ii, B → i, C → iv, D → iii
• Option D: A → ii, B → iii, C → iv, D → i

Hence, the correct answer is Option C.