What should come in place of the question mark (?) in the following question ?
$$(49)^{2}\times(7)^{8}\div(343)^{3}=(7)^{?}$$
Let the required number be X.
So, $$(49)^{2}\times(7)^{8}\div(343)^{3}=(7)^{X}$$
Hence, $$7^4 \times 7^8 \div 7^9 = 7^X$$
Hence, $$7^{4+8-9} = 7^X$$
Therefore, $$7^3 = 7^X$$
Hence, $$X=3$$
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