Two particles $$A$$ and $$B$$ of equal mass $$M$$ are moving with the same speed $$v$$ as shown in figure. They collide completely inelastic and move as a single particle $$C$$. The angle $$\theta$$ that the path of $$C$$ makes with the X-axis is given by-

A

$$\tan \theta = \dfrac{\sqrt{3} - \sqrt{2}}{1 - \sqrt{2}}$$

B

$$\tan \theta = \dfrac{1 - \sqrt{2}}{\sqrt{2}(1 + \sqrt{3})}$$

C

$$\tan \theta = \dfrac{1 - \sqrt{3}}{1 + \sqrt{2}}$$

D

$$\tan \theta = \dfrac{\sqrt{3} + \sqrt{2}}{1 - \sqrt{2}}$$