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If x = -0.5, then which of the following has the smallest value?
$$2^{1/x}$$
$$1/x$$
$$1/x^2$$
$$2^x$$
$$1/\sqrt{-x}$$
$$2^p$$ is always positive
$$x^2$$ is always non negative.
$$1/\sqrt{-x}$$ is always positive.
$$\frac{1}{x}$$ is negative when x is negative.
In this case, x is negative => $$\frac{1}{x}$$ is smallest.
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