If sin (A - B) = $$\frac{1}{2}$$ and cos (A + B) = $$\frac{1}{2}$$ where A > B > 0 and A + B is an acute angle, then the value B is
sin(A-B) = 1/2 $$\Rightarrow$$ A-B =Â $$\frac{\pi}{6}$$ -------(1)
cos(A+B) = 1/2Â $$\Rightarrow$$ A+B =Â $$\frac{\pi}{3}$$ -------(2)
on solving (1) & (2)
A =Â Â $$\frac{\pi}{4}$$
B =Â Â $$\frac{\pi}{12}$$
so the answer is option C.
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