Question 49

The ages of A and B differ by 16 years. If 6 years ago, the elder one was 3 timesas old as the younger one, find the present age of the younger between A and B?

Solution

Let the age of younger person be x

Thus, the age of the elder person is (x+16),

Their ages 6 years ago,
3(x-6) = (x+16-6)

=> 3x -18 = x+10

=> x = 14

the present age of the younger between A and B = 14 years

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