lf the equations $$x^{2}+mx+9=0, x^{2}+nx+17=0$$ and $$x^{2}+(m+n)x+35=0$$ have a common negative root, then the value of $$(2m+3n)$$ is

When given more than one equations, stating the fact that there is a common root, 
We need to equate the two equations to get discernible values for $$x$$

Here, we are given three equations with the values of $$m$$, $$n$$

$$x^2+mx+9=x^2+\left(m+n\right)x+35$$
$$mx+9=mx+nx+35$$
$$nx=-26$$

Similarly, we can do it for the other equation as well, 
$$x^2+nx+17=x^2+\left(m+n\right)x+35$$
$$mx=-18$$

Substituting the value of either $$mx$$ or $$nx$$ in the original equations, we get 
$$x^2-18+9=0$$
$$x^2=9$$
$$x=\pm\ 3$$
Since we are given that the root is negative, $$x=-3$$

$$n=-\frac{26}{-3}$$
$$m=-\frac{18}{-3}$$

$$3n=26$$
$$2m=12$$

$$2m+3n=38$$