In the reaction given below, the product 'X' is:

$$LiAlH_4$$ is a powerful reducing agent so, it will completely reduces primary amides down to primary amines by converting the carbonyl carbon into a methylene group ($$-CH2-$$). AND The ketone carbonyl group is cleanly reduced to a secondary alcohol group.

$$LiAlH_4$$ is a nucleophilic reducing agent, meaning it attacks electron-deficient carbon atoms (like carbonyls). It does not reduce ordinary isolated carbon-carbon double bonds because alkenes are electron-rich and repel nucleophilic attack. Therefore, the central double bond remains completely unaffected.

Hence Final structure would be C