Two identical large thin metal plates carrying charges $$+q_1$$ and $$+q_2$$, respectively, with $$q_1 > q_2$$, are kept close at a distance $$d$$ apart and parallel to each other to form a parallel plate capacitor of capacitance $$C$$. The potential difference between the plates is

A

$$\frac{q_1 - q_2}{C}$$

B

$$\frac{q_1 - q_2}{2C}$$

C

$$\frac{q_1 - q_2}{4C}$$

D

$$\frac{q_1 + q_2}{2C}$$