Question 47

If $$(\sqrt{\frac{7}{5}})^{3x-y}=\frac{875}{2401}$$ and $$(\frac{4a}{b})^{6x-y}=(\frac{2a}{b})^{y-6x}$$, for all non-zero real values of a and b, then the value of $$x+y$$ is

Correct Answer: 14





3x-y = -6


Therefor, y=6x as the bases are different so the power should be zero for the results to be equal.


or, 3x - 6x = -6

or x= 2

y= 6x = 12

x+y = 14

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