Question 47

A bag contains 2 red, 3 green and 2 blue balls. 2 balls are to be drawn randomly. Whatis the probability that the balls drawn contain no blue ball?

Solution

There are 2 red, 3 green and 2 blue balls

Probability of drawing blue balls = $$\frac{2}{7}$$

=> Probability that the balls drawn contain no blue ball = $$1-\frac{2}{7}$$

= $$\frac{5}{7}$$

=> Ans - (A)


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