Question 46

The two roots of an quadratic equation are given as $$x =\frac{2}{3}$$ ; and $$x = \frac{-1}{2}$$  The equation can be written as:

Solution

The correct option is 

The required quadratic equation is ($$x-\frac{2}{3})$$ ($$x+\frac{1}{2}$$)=0

 $$\Rightarrow$$ ($$3x-2$$)($$2x+1$$) = 0


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