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In triangle $$ABC$$, $$AD \bot BC$$ and $$AO$$ is the bisector of $$\angle{BAC}$$. If $$\angle{ABC} = 65°$$ and $$\angle{ACB} = 23\frac{1°}{2}$$, then $$\angle{DAO}$$ is ...............(in degrees)
$$20\frac{1°}{4}$$
$$20\frac{1°}{5}$$
$$20\frac{1°}{2}$$
$$20\frac{3°}{4}$$
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