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A vessel is fully filled with a special liquid. Four litres of liquid is drawn out of this vessel and is replaced with water. If the ratio of the special liquid to the water becomes 1 : 2, then what is the capacity of the vessel?
Let capacity of vessel be $$x$$ litres
Now, special liquid in the vessel = $$(x-4)$$ litres and water = $$4$$ litres
=> Ratio = $$\frac{x-4}{4}=\frac{1}{2}$$
=> $$x-4=2$$
=> $$x=6$$
$$\therefore$$ Capacity of vessel = 6 litres
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